Optimization of the flexural rigidity of a concentric pipe used in transmitting rotation for arcshaped forceps
 Satsuya Noda†^{1}Email authorView ORCID ID profile,
 Toshio Takayama†^{2} and
 Toru Omata†^{2}
DOI: 10.1186/s4064801700773
© The Author(s) 2017
Received: 20 August 2016
Accepted: 3 March 2017
Published: 31 March 2017
Abstract
Arcshaped forceps are important in pharyngeal cancer surgery, endoscopic sinus surgery, and single port surgery. Rotating the gripper of an arcshaped forceps with respect to its shaft axis can improve the manipulability of the forceps. Concentric pipe structures consisting of inner and outer pipes are often used for this purpose. The inner pipe transmits rotations from its proximal end to distal end. However, the shape of the bent inner pipe is generally different from that of the outer pipe, and this causes large friction between the outer and inner pipes. To reduce friction, a plastic tube is often used for the inner pipe. However, since its torsional rigidity is low, this results in a large twist angle. This paper proposes a procedure to fit a metal bent inner pipe to an outer pipe by adjusting the flexural rigidity of the inner pipe with slits to reduce the friction. The procedure minimizes the twist angle between the proximal and distal end of the arcshaped forceps by reducing the torque required to rotate its metal inner pipe. We develop a 5 mm forceps with a 3.5 mm inner pipe. The twist angle is 2.8° when a load torque of 20 Nmm is applied, which is a typical load torque for suturing, whereas the twist angle of a PEEK (polyetheretherketone) inner pipe is 24.3° in simulation. Ex vivo experiments show that the required forceps torque is small in simulated clinical scenarios.
Keywords
Concentric pipe Arcshaped forceps Single port surgery Pharyngeal cancer surgery Flexural rigidity SlitBackground
Arcshaped forceps are important in pharyngeal cancer surgery, endoscopic sinus surgery [1], and single port surgery [2]. The use of a linearshaped forceps in pharyngeal cancer surgery requires a patient to bend his or her neck backwards and increases the burden on the patient when compared with the surgery performed by an arcshaped forceps. In single port surgery, the direction of the gripper attached at the end of a linearshaped forceps is limited to that of the trocar as shown in Fig. 1a. The use of arcshaped forceps can accommodate the direction of the gripper.
The manipulability of a forceps can be improved if its gripper can rotate about its shaft axis [3]. With respect to a linearshaped forceps, the rotation of the proximal end simply generates the rotation of the distal end as shown in Fig. 1a. However, in an arcshaped forceps, the rotation of the proximal end moves the position of the distal end as shown in Fig. 1b. There are two types of structures to rotate the distal end, namely multijoint and concentric pipe structures. Although the multijoint structure enables the smooth rotation of the end of a forceps, it is complex and consists of several parts.
Generally, the shape of the bent inner pipe is different from that of the outer pipe as shown in Fig. 2. This causes contact between the outer and inner pipes, resulting in friction. A load torque as well as the friction increases the torque to rotate the inner pipe. A typical load torque for suturing is 20 Nmm [10]. Using a low friction plastic tube (e.g. PEEK/PTFE composite) for the inner pipe would be valid to reduce friction. However, the Young’s modulus of plastic is much lower than that of metal and the torsional rigidity is also low, which results in a large twist angle.
This study proposes a procedure to fit the bent metal inner pipe with respect to the outer pipe such that only the two ends of the pipes are in contact with each other by adjusting the flexural rigidity of the inner pipe with slits as shown in Fig. 2b. Thus, the friction between the pipes can be reduced even if the inner pipe touches the outer pipe in areas other than the ends of the pipes. An inner pipe with optimally adjusted slit intervals can minimize the twist angle.
Adjustment of the flexural rigidity with slits
Lower flexural rigidity is necessary for an inner pipe. However, torsional rigidity decreases and the twist angle increases as flexural rigidity decreases. Hence, this study proposes an optimization procedure to minimize the twist angle. The ease of manufacturing is also important to develop a practical medical tool, and it is also required to adjust the flexural rigidity within the accuracy of machine tools. In this study, the flexural rigidity of an inner pipe with slits is adjusted.
Equivalent moment of inertia of area
Slit pattern
Various slit patterns exist in shaft couplings and in flexible forceps [12]. In order to enable the ease of manufacturing, two patterns as shown in Fig. 3 are considered, and the pattern that provided low flexural rigidity and high torsional rigidity was selected. The inner pipe has slits in a direction vertical to the paper surface and has the same flexural rigidity in all radial directions. I and \(I_p\) are calculated by using Mechanica (pro/Engineer). The shape parameters are as follow (see Fig. 3a, c, e):
Outer diameter: \(d_2=6\) mm
Inner diameter: \(d_1=5\) mm
Slit interval \(e = 1.4\) mm
Slit interval \(a=1.2, 1.6, 2.0, 2.4\) and 3.0 mm
Figure 4 shows the calculation results. The vertical axis is denoted by \(I_p\), and the horizontal axis is denoted by I. It is observed that \(I_p\) in Pattern A is higher than that in Pattern B with the same I. Thus, Pattern A is selected in this study.
Boundary condition of the ends
Generally, arcshaped forceps for pharyngeal cancer surgery or for single port surgery have a curved portion in the distal end region, which is close to the affected part. In contrast, the forceps have a linear portion in the proximal end region in which a handle is attached.
Procedure to optimally adjust the flexural rigidity
 Step 1:
Develop the database of I, \(I_p\), Z, and \(Z_p\) by varying the parameters for the slit.
 Step 2:
Set a target line, and calculate the curvature along the line.
 Step 3:
Calculate I, and determine the range of \(f_H\), which corresponds to the contact force acting on the proximal end. Define the range as \(f_{{\text{min}}} \le f_H \le f_{{\text{max}}}\).
 Step 4:
Determine \(f_H\) that minimizes the twist angle of the inner pipe \(\phi \) in the range \(f_{{\text{min}}} \le f_H \le f_{{\text{max}}}\). Calculate \(\phi \) for each sampled \(f_H\) as follows;
 Step 4.1:
Discretize the distribution of I.
 Step 4.2:
Confirm that the stress on the inner pipe is lower than the maximum permitted stress and that the error between the target and designed lines is less than the given allowable error. If the candidate does not meet these conditions, then it is discarded.
 Step 5:
Select \(f_H\) that minimizes \(\phi \). If no candidates remain, then return to Step 2 and modify the target line. A solution is more likely to exist if the curvature of the forceps is reduced.
Step 1
The following values were selected for the slit parameters of the inner pipe. Their intervals are the smallest possible for usual machine tools.
\(a = 1.2, 1.6, 2.0, 2.4, 3.0\) mm
\(e = 1.0, 1.4, 1.8\) mm
\(c = 0.3, 0.4, 0.5\) mm
Calculate I for all combinations of the above cut parameters and sort the calculations in ascending order (\(I_1<I_2< \cdots < I_{45}\)). This is defined as the database of I. Similarly, \(I_p\), Z and \(Z_p\) are calculated corresponding to the I database.
Step 2
Step 3
Figure 6 shows the forces and moments acting on the inner pipe, which is in contact with the outer pipe only at its ends. The following symbols are defined:
\(T_m\): axial torque acting on the inner pipe between the proximal and distal ends
\(T_\mathrm{OUT}\): output torque at the distal end of the inner pipe
\(f_{z0}\): contact force in the z direction
\(C_1\) and \(C_2\): two contact points at the distal end
k: distance between \(C_1\) and \(C_2\)
\(f_{y1}\) and \(f_{y1}\): couple of forces acting at \(C_1\) and \(C_2\) in the y direction
\(f_{z1}\) and \(f_{z1}\): couple of forces acting at \(C_1\) and \(C_2\) in the z direction
\(M_y\) moment about the Yaxis generated by \(f_{z1}\) and \(f_{z1}\).
\(f_H\) is sampled in the range \(f_{min} \le f_H \le f_{max}\) to evaluate the angle \(\phi \) becuase the monotonicity of \(\phi \) in Eq. (23) cannot be determined as the value of \(f_H\) increases.
Note 2: \(I_p\) of the denominator monotonically increases as the value of I increases as shown in Fig. 4. From Eq. (10), I weakly increases as the value of \(f_H\) increases. Thus, \(I_p\) weakly increases as the value of \(f_H\) increases. \(T_m\) of the numerator also monotonically increases as the value of \(f_H\) increases.
Step 4
The following are calculated for each \(f_{H_j}= f_{min}+j\Delta h\) where \(\Delta h=(f_{max}f_{min})/N\) and \(j=0, \ldots , N\).
Step 4.1
 1.
In \(I_1, \ldots , I_{45}\) of the database, the set of \(I_i\) that satisfies \(\mathrm{min} I(s) \le I_i \le \mathrm{max}I(s) \) is determined. It is assumed that \(I_a< I_{a+1}< \cdots < I_{b}\) are such \(I_i\).
 2.
Let \(A_1\), \(A_2, \ldots\), and \(A_\mathrm{n}\) denote the intersection points between \(I_a< I_{a+1}< \cdots < I_{b}\) and I(s) in the ascending order of s.
 3.
Let \(\hat{I_1}\), \(\hat{I_2}\), \(\ldots \), and \(\hat{I_n}\) denote the values of I(s) at points \(A_1, A_2, \ldots\), and \(A_\mathrm{n}\), respectively.
 4.
\(B_{i}\) be the middle point between \(A_i\) and \(A_{i+1}\) on the s axis, where \(i=1, \ldots , n1\).
 5.
For each interval \(O B_1\), \(B_1 B_2\), \(\ldots \), and \(B_{n1}A_n\), I(s) can be discretized as \(\hat{I_1}\), \(\hat{I_2}\), \(\ldots \), and \(\hat{I_n}\), respectively.
Step 4.2
The following three procedures are executed for confirmation:
Simple stress confirmation
\(\sigma _\mathrm{net}\) should be calculated. However, the slits of the inner pipe makes the calculation of \(\sigma _\mathrm{net}\) from \(\sigma _s\) and \(\tau _s\) difficult. In many cases of this study, \(\sigma _s \gg \tau _s\). Moreover, the stress concentration points of the bending load are different from those of the torsional load as will be described in the simulation section. Therefore, this step regards that \(\sigma _\mathrm{net} \approx \sigma _s\) and excludes the jth candidate \(f_{Hj}\) if \(\sigma _s>\sigma _\mathrm{proof}\).
Error
The maximum error between the target and the designed lines is denoted by \(\varepsilon \). It is confirmed that the calculated value is smaller than a given allowable error \(\bar{\varepsilon }\) . If \(\varepsilon <\bar{\varepsilon }\), then the procedure moves to the next step. If \(\varepsilon >\bar{\varepsilon }\), then the sampling intervals are randomly selected and modified by several millimeters, and the procedure returns to Step 4.2 (1). It should be noted that this random search is practical because the number of the sampling intervals is expected to be less than 10. If \(\varepsilon >\bar{\varepsilon }\) after this procedure, then \(f_{H_j}\) is excluded.
Final stress confirmation
\(\sigma _\mathrm{net}\) is calculated by using FEM. The jth candidate is excluded, if \(\sigma _\mathrm{net} > \sigma _\mathrm{proof}\).
Step 5
The final step involves selecting \(f_{H_j}\) that minimizes \(\phi \). \(\phi \) of each candidate is obtained by Eq. (23). If no candidates of \(f_{H_j}\) remain, then the procedure returns to Step 2 and modifies the target line by reducing its curvature.
Simulation and experiment
Simulation of 8 mm forceps
Candidate of \(f_H\) for the 6 mm inner pipe
Candidate No.  \(f_H\) (N)  \(\phi \) (°)  \(\varepsilon \) (mm) 

1st candidate  0.03  7.60  0.59 
2nd candidate  0.05  5.48  0.39 
3rd candidate  0.08  5.31  1.42 
4th candidate  0.10  4.46  2.25 
5th candidate  0.13  4.30  1.25 
6th candidate  0.15  4.33  0.61 
Slit parameters and errors of the 6 mm inner pipe of the 5th candidate
\(\mathrm{O B_1}\) (mm)  38 
a (mm)  1.6 
e (mm)  1.8 
c (mm)  0.3 
\(\mathrm{B_1 B_2}\) (mm)  31 
a (mm)  2.0 
e (mm)  1.0 
c (mm)  0.4 
\(\mathrm{B_2 B_3}\) (mm)  57 
a (mm)  2.0 
e (mm)  1.4 
c (mm)  0.5 
\(\varepsilon \) (mm)  1.25 
Figure 8(1) shows the bent shape of the inner pipe. For purposes of comparison, Fig. 8(2) shows the line with slits cut uniformly, and (3) shows the line with no slits. In (3), \(f_H\) is such that the maximum stress \(\sigma _s\) is equal to the proof stress \(\sigma _\mathrm{proof}\). Line (1) is close to the target line (\(\varepsilon \) = 1.25 mm) whereas Lines (2) and (3) are not close to the target line (\(\varepsilon \) = 16.54, 161.9 mm). From Eq. (23), the twist angle is \(\phi = 4.30\)° in (1).
Note 4: The twist angle can also be obtained from the FEM simulation. It is \(\phi =4.18\)° and close to the twist angle from Eq. (23)
Simulation of 5 mm forceps
An arcshaped forceps with diameter of 5 mm is simulated. Figure 9 shows the target line with the shape parameters \(R_0= 350\) mm, \(\theta = 30\)° and \(L=300\) mm. This line is determined by referring to a forceps for pharyngeal cancer surgery that is practically used and a forceps for single port surgery (for example, Type KTY1 of ADACHITANKO forceps [13]).
Candidate of \(f_H\) for the 3.5 mm inner pipe
Candidate No.  \(f_H\) (N)  \(\phi \) (°)  \(\varepsilon \) (mm) 

1st candidate  0.10  4.41  1.08 
2nd candidate  0.15  3.48  3.94 
3rd candidate  0.20  3.25  0.85 
4th candidate  0.25  2.99  1.63 
5th candidate  0.30  2.93  1.45 
Slit parameters and errors for the 3.5 mm inner pipe of the 5th candidate
\(\mathrm{O B_1}\) (mm)  102 
a (mm)  1.6 
e (mm)  1.4 
c (mm)  0.3 
\(\mathrm{B_1 B_2}\) (mm)  81 
a (mm)  1.6 
e (mm)  1.4 
c (mm)  0.4 
\(\varepsilon \) (mm)  1.50 
Specification of the 5th candidate
Material  SUS630  Ti6Al4V  SUS304 

E (GPa)  205  113  192 
\(\sigma _\mathrm{proof}\) (MPa)  1175  828  205 
\(\sigma _s\) (MPa)  1144  631  1071 
\(\tau _s\) (MPa)  157  139  155 
\(\sigma _\mathrm{net}\) (MPa)  1166  709  1131 
\(\phi \) (°)  2.93  4.93  3.12 
Table 5 lists the details of the calculation for the 5th candidate. Although the sum of \(\sigma _s\) and \(\tau _s\) exceeds \(\sigma _\mathrm{proof}\) in Step 4.2 (1), \(\sigma _\mathrm{net}\) = 1169 MPa in Step 4.2 (3), which is smaller than \(\sigma _\mathrm{proof}\). In any slit, the stress concentration point of the bending load is different from that of the torsional load. Figure 10 shows an example of the FEM results. In addition, the twist angle of a PEEK pipe without slits (Young’s modulus: 4.1 GPa, 0.2% Proof stress: 163 MPa) was computed for comparison. It was 24.3° even when no friction is assumed, which is much larger than 2.93°.
Similarly, Table 5 lists the results when the material of the inner pipe was replaced with Ti6Al4V and the usual stainless steel SUS304. Ti6Al4V has low Young’s modulus and similar proof stress as SUS630. This results in a lower \(\sigma _\mathrm{net}\) but larger twist angle: \(\phi \) = 4.93°. However, the twist angle is still much smaller than that of the PEEK pipe.
Development of 5 mm arcshaped forceps and measurement of rotation torque and twist angle
To confirm the result of the SUS630 inner pipe, SUS304 was selected to develop the forceps for the experiments owing to its immediate availability. The Young’s modulus of SUS304 is 192 GPa, and its 0.2% proof stress is 205 MPa. Although the maximum stress exceeds the proof stress of SUS304, it does not mean that metal fatigue occurs immediately. It can withstand for a certain period. Figure 11 shows the developed forceps.
The torque to rotate the distal end of the inner pipe when no load is applied is measured. An inner pipe with no slits is also prepared for comparison purposes. A handle (material: ABS (acrylonitrilebutadienestyrene), diameter: 20 mm) with a cable was installed on the proximal end, and a force gage measured the tension force. The experiments did not involve the use of bearings. The torque to rotate the distal end is 5.1 Nmm, whereas that of the noslit pipe is 37.0 Nmm. The distal end of the developed pipe can be rotated manually, whereas that of the noslit pipe cannot be rotated manually. The twist angle is 2.8° when a load torque of 20 Nmm is applied. The result is as small as the simulation result and considerably less than 24.3°.
Ex vivo experiment
In the ex vivo experiment, chicken liver, minced pork meat and porcine blood were used. In the chicken liver experiment, the distal end of the forceps was inserted into the slit cut of the liver, as shown in Fig. 12a, so that organic materials could fill the space of the forceps. In the minced pork meat experiment, water was added to produce a liquid condition, as shown in Fig. 12b. Figure 12c shows the image of minced meat, as observed with a microscope. Particles with a diameter of approximately 0.2 mm are seen. Figure 12d shows the ex vivo experiment involving the insertion of forceps into the blood. Approximately 30 mm length of the slit distal side of the forceps was inserted into the blood. Because the purchased blood included 10% anticoagulant (3.23% sodium citrate solution), 2% coagulant (2% calcium chloride solution) was added. The distal end of the forceps was rotated two revolutions every 30 s, for a duration of 4 h. Moreover, the blood was poured into the outer pipe and the inner pipe was inserted into the outer pipe, considering the case of blood invasion into the forceps.
After the ex vivo experiments, we measured the torque required to rotate the inner pipe when no load was applied to the distal end. In the chicken liver experiment, it increased from 5.1 to 5.3 Nmm, in the minced pork meat experiment, it increased from 5.1 to 5.4 Nmm, and in the porcine blood experiment, it decreased from 5.1 to 3.8 Nmm. Moreover, 2h after the insertion of blood into the outer pipe, it increased from 5.1 to 5.3 Nmm. These increases are small.
Discussion
Ex vivo experiment
In the experiments involving the forceps, the twist angle is 2.8° when a load torque of 20 Nmm is applied. In the ex vivo experiments, the maximum increase of the torque required to rotate the inner pipe is only 0.3 Nmm. Therefore, the increase of the twist angle can be expected to be small.
In the chicken liver and minced pork experiments, the small increase in the torque was resulted from the little invasion of organic material into the forceps. In the experiments of the forceps insertion to the blood, the decrease in the torque was caused by fluid lubrication of the blood. In the experiments of the blood impregnation into the outer pipe, the small increase in the torque resulted from gellike blood clots between the outer and inner pipes. Blood coagulates and forms blood clots, which are fragile gel materials unless they dry out. The blood clots did not dry out because the inner pipe was not exposed to the atmosphere. For this reason, we consider that the blood clot remains as a gel material and fixing does not arise.
Other methods to reduce friction
The use of PTFE coating is a valid method to reduce friction. The coefficient of friction is typically 0.1. However, the PTFE coating has low wear resistance and therefore cannot be used on metal–metal contact [14]. In reference [15], PTFE coating is used under low contact pressure.
Sterilization
 1.
The wire unit is pulled from the inner pipe from its distal end.
 2.
The inner pipe is pulled from the outer pipe from its proximal end.
Conclusion
To improve the manipulability of arcshaped forceps, this paper discusses the method of the design of the shaft axis. Usually, concentric pipe structures are used to transmit the rotational motion of the proximal end to the distal end of the gripper. In this method, the shape of the bent inner pipe is different from that of the outer pipe. This causes strong contact between the outer and inner pipes if the inner pipe has strong flexural rigidity. This causes a large friction torque and a large angle difference (twist angle) between the distal end and the proximal end of the inner pipe. A low friction and elastic plastictube for the inner pipe would be valid to reduce the required torque. However, the Young’s modulus of plastic is significantly lower than that of metal and the torsional rigidity is also low, which results in a large twist angle. This paper proposes a procedure to fit the bent inner pipe to the outer pipe such that only the ends of the pipes are in contact with each other. The inner pipe with slits adjusts its flexural rigidity. The proposed method can be applied to various curves.

Different slit intervals and width change the flexural rigidity of the inner pipe. First, the database of the equivalent flexural rigidity is developed. Repeat the following by changing the contact force between the inner and outer pipes.

The desired distribution of the flexural rigidity of the inner pipe is calculated from the outer pipe curve.

It is discretized by applying the database.

The candidate is excluded if the stress and error are larger than the allowable values.

Slit pattern of the minimum twist angle is selected among the candidates.

In the 8 mm forceps (Ti6Al4V) simulation, the twist angle was 4.30°.

In the 5 mm forceps (SUS630) simulation, the twist angle was 2.93°, whereas the twist angle of the PEEK inner pipe was 24.3°.

In the 5 mm forceps experiments, SUS304 was selected, which has a similar Young’s modulus to SUS630. The twist angle of 2.8° was consistent with the simulation result.

In the ex vivo experiments, the forceps were inserted into the chicken liver, minced pork meat, and porcine blood the rotation torque was measured. It changed from 5.1 to 5.3, 5.4, and 3.8 Nmm respectively. Moreover, it was 5.3 Nmm when blood was poured in the outer pipe and coagulated. These increase are small.
Notes
Declarations
Authors' contributions
All authors equally contributed. All authors read and approved the final manuscript.
Competing interests
The authors declare that they have no competing interests.
Open AccessThis article is distributed under the terms of the Creative Commons Attribution 4.0 International License (http://creativecommons.org/licenses/by/4.0/), which permits unrestricted use, distribution, and reproduction in any medium, provided you give appropriate credit to the original author(s) and the source, provide a link to the Creative Commons license, and indicate if changes were made.
Authors’ Affiliations
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